QJEEM16Chc905: JEE Main 2016 Chemistry - Class 11 JEEM16Chc905 Solution: The volume of 0.1N dibasic acid sufficient to neutralize 1 g of …

According to law of equivalence,

Equivalence of acid = Equivalence of base.

Equivalence of acid = Normality x volume = 0.1 $\times$ v

As we know base produce OH ^$-$ ion, so moles of base is same as moles of OH ^$-$ ion = 0.04

Another formula of equivalence = n factor $\times$ number of moles

$\therefore\,\,\,$ Equivalance of base = n factor of OH ^$-$ $\times$ moles of OH ^$-$ = 1 $\times$ 0.04

As for any ion, the charge of that ion is the n factor of that ion. Here OH ^$-$ has 1 negative charge so it's n factor = 1

$\therefore\,\,\,$ 0.1 $\times$ v = 1 $\times$ 0.04

$\Rightarrow$ $\,\,\,$ v = 0.4 L

=   0.4 $\times$ 1000

=    400 ml.