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QJEEM16Cha713: JEE Main 2016 Chemistry - Class 11 JEEM16Cha713 Solution: The plot shows the variation of − l n K p versus temperature…

The plot shows the variation of −ln Kp versus temperature for the two reactions.

M(s) + 12 O2(g) → MO(s) and

C(s) + 12 O2(g) → CO(s)

JEE Main 2016 (Online) 9th April Morning Slot Chemistry - Thermodynamics Question 149 English
Identify the correct statement :

Multiple Choice Options

  • A At T > 1200 K, carbon will reduce MO(s) to M(s).
  • B At T < 1200 K, the reaction MO(s) + C(s) → M(s) + CO(g) is spontaneous.
  • C At T < 1200 K, oxidation of carbon is unfavourable
  • D Oxidation of carbon is favourable at all temperatures.

Step-by-Step Verified Solution

Carbon is a good reducing agent for oxides. The reason why carbon reduces metal oxide spontaneously at T < 1200 K is that −ln⁡KpT line for CO has a negative slope.

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