QJEEM16Ch1081: JEE Main 2016 Chemistry - Class 12 JEEM16Ch1081 Solution: The reaction of ozone with oxygen atoms in the presence of…

Question

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The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by a two step process shown below :

O₃(g) + Cl

{^ \bullet }

(g)

\to

O₂(g) + ClO

{^ \bullet }

(g) . . . . . .(i)

k_i = 5.2 × 10⁹ L mol⁻¹ s⁻¹

ClO

{^ \bullet }

(g) + O

{^ \bullet }

(g)

\to

O₂(g) + Cl

{^ \bullet }

(g) . . . . . . (ii)

k_ii = 2.6 × 10¹⁰ L mol⁻¹ s⁻¹

The closest rate constant for the overall reaction O₃(g) + O

{^ \bullet }

(g)

\to

2 O₂(g) is :

Accepted Answer

We have

${O_3}(g) + C{l^ \bullet }(g) \to {O_2}(g) + Cl{O^ \bullet }(g)$ ...... (1)

$Cl{O^ \bullet }(g) + {O^ \bullet }(g) \to {O_2}(g) + C{l^ \bullet }(g)$ ...... (2)

On adding Eq. (1) and Eq. (2), we get the required equation for overall reaction

${O_3}(g) + {O^ \bullet }(g) \to 2{O_2}(g)$

Therefore,

${k_{overall}} = {k_1} \times {k_2}$

$= 5.2 \times {10^9} \times 2.6 \times {10^{10}}$

$= 1.4 \times {10^{20}}$ L mol^{$-$ 1} s^{$-$ 1}

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