Verified Solution • 2025–26 Session moderate

QJEEM16Ch0c87: JEE Main 2016 Chemistry - Class 12 JEEM16Ch0c87 Solution: Identify the correct trend given below : (Atomic No.=Ti : 22,…

Identify the correct trend given below : (Atomic No.=Ti : 22, Cr : 24 and Mo : 42)

Multiple Choice Options

  • A Δo of [Cr(H2O)6]2+ > [Mo(H2O)6]2+ and Δo of [Ti(H2O)6]3+ > [Ti(H2O)6]2+
  • B Δo of [Cr(H2O)6]2+ > [Mo(H2O)6]2+ and Δo of [Ti(H2O)6]3+ < [Ti(H2O)6]2+
  • C Δo of [Cr(H2O)6]2+ < [Mo(H2O)6]2+ and Δo of [Ti(H2O)6]3+ > [Ti(H2O)6]2+
  • D Δo of [Cr(H2O)6]2+ < [Mo(H2O)6]2+ and Δo of [Ti(H2O)6]3+ < [Ti(H2O)6]2+

Step-by-Step Verified Solution

Δ0 of complex [Mo(H2O)6]2+ is greater than that of [Cr(H2O)6]2+. It is due to the fact that Mo2+ belongs to second row transition element while Cr2+ is first row transition element.

Magnitude of crystal field splitting energy (Δ0) depends on the charge on the metal ion. Greater the charge, greater is the crystal field splitting energy. Therefore, [Ti(H2O)6]3+ > [Ti(H2O)6]2+.

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