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QJEEM15Ma2e5b: JEE Main 2015 Mathematics - Class 11 JEEM15Ma2e5b Solution: Let be the vertex and be any point on the parabola, . If the…

Let OO be the vertex and QQ be any point on the parabola, x2=8y{{x^2} = 8y} . If the point PP divides the line segment OQOQ internally in the ratio 1:31:3 , then locus of PP is :

Multiple Choice Options

  • A y2=2x{y^2} = 2x
  • B x2=2y{{x^2} = 2y}
  • C x2=y{{x^2} = y}
  • D y2=x{y^2} = x

Step-by-Step Verified Solution

Let the coordinates of Q and P be (x1, y1) and (h, k) respectively.

∵\because Q lies on x2 = 8y,

∴\therefore x 12_1^2 = 8y ....... (1)

Again, P divides OQ internally in the ratio 1 : 3.

∴\therefore h=x1+04=x14h = {{{x_1} + 0} \over 4} = {{{x_1}} \over 4} or x1 = 4h and

k=y1+04=y14k = {{{y_1} + 0} \over 4} = {{{y_1}} \over 4} or y1 = 4k

JEE Main 2015 (Offline) Mathematics - Parabola Question 120 English Explanation

Now putting x1 and y1 in (1) we get,

16h2 = 32k or, h2 = 2k

∴\therefore the locus of P is given by, x2 = 2y.

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