Verified Solution • 2025–26 Session moderate

QJEEM15Ch3b1c: JEE Main 2015 Chemistry - Class 11 JEEM15Ch3b1c Solution: The ionic radii (in Å) of N 3– , O 2– and F – are respectively:

The ionic radii (in Å) of N3–, O2– and F– are respectively:

Multiple Choice Options

  • A 1.36, 1.71 and 1.40
  • B 1.71, 1.40 and 1.36
  • C 1.71, 1.36 and 1.40
  • D 1.36, 1.40 and 1.71

Step-by-Step Verified Solution

Here all of them are isoelectric and for isoelectric species size of anion increases as negative charge increases.

So, correct order is :

N3– > O2– > F–

∴ Radius of N3– = 1.71 Å

and Radius of O2– = 1.40 Å

and Radius of F– = 1.36 Å

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