QJEEM15Ch111e: JEE Main 2015 Chemistry - Class 12 JEEM15Ch111e Solution: Two Faraday of electricity is passed through a solution of CuSO …

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Two Faraday of electricity is passed through a solution of CuSO₄. The mass of copper deposited at the cathode is: (at. mass of Cu = 63.5 amu)

Accepted Answer

C u^{2 +} + 2 e^{-} \overset{}{⟶} C u

2F\,\,i.e.\,\,2 \times 96500\,C

deposit

Cu=1

mol

=63.5

g

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