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QJEEM14Phd532: JEE Main 2014 Physics - Class 12 JEEM14Phd532 Solution: In the circuit shown here, the point is kept connected to point …

In the circuit shown here, the point ′C′'C' is kept connected to point ′A′'A' till the current flowing through the circuit becomes constant. Afterward, suddenly, point ′C′'C' is disconnected from point ′A′'A' and connected to point ′B′'B' at time t=0.t=0. Ratio of the voltage across resistance and the inductor at t=L/Rt=L/R will be equal to : JEE Main 2014 (Offline) Physics - Alternating Current Question 154 English

Multiple Choice Options

  • A e1−e{e \over {1 - e}}
  • B 11
  • C −1-1
  • D 1−ee{{1 - e} \over e}

Step-by-Step Verified Solution

Applying kirchhoffs law of voltage in closed loop

−VR−VC=0⇒VRVC=−1- {V_R} - {V_C} = 0 \Rightarrow {{{V_R}} \over {{V_C}}} = - 1

JEE Main 2014 (Offline) Physics - Alternating Current Question 154 English Explanation

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