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QJEEM14Pha1e5: JEE Main 2014 Physics - Class 12 JEEM14Pha1e5 Solution: Two beams, and , of plane polarized light with mutually…

Two beams, AA and BB , of plane polarized light with mutually perpendicular planes of polarization are seen through a polaroid. From the position when the beam AA has maximum intensity (and beam BB has zero intensity), a rotation of polaroid through 30∘{30^ \circ } makes the two beams appear equally bright. If the initial intensities of the two beams are IA{{\rm I}_A} and IB{{\rm I}_B} respectively, then IAIB{{{{\rm I}_A}} \over {{{\rm I}_B}}} equals:

Multiple Choice Options

  • A 33
  • B 32{3 \over 2}
  • C 11
  • D 13{1 \over 3}

Step-by-Step Verified Solution

According to malus law, intensity of emerging beam is given by,

I=I0cos⁡2θI = {I_0}{\cos ^2}\theta

Now, IA′=IAcos⁡230∘{I_{A'}} = {I_A}{\cos ^2}{30^ \circ }

IB′=IBcos⁡260∘{I_{B'}} = {I_B}{\cos ^2}{60^ \circ }

As IA′=IB′{I_{A'}} = {I_{B'}}

⇒IA×34=IB×14\Rightarrow {I_A} \times {3 \over 4} = {I_B} \times {1 \over 4}

∴\therefore IAIB=13{{{I_A}} \over {{I_B}}} = {1 \over 3}

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