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QJEEM14Ph6d8f: JEE Main 2014 Physics - Class 11 JEEM14Ph6d8f Solution: When a rubber-band is stretched by a distance x , it exerts…

When a rubber-band is stretched by a distance x, it exerts restoring force of magnitude F=ax+bx2 where a and b are constants. The work done in stretching the unstretched rubber-band by L is :

Multiple Choice Options

  • A aL2+bL3
  • B 12(aL2+bL3)
  • C aL22+bL33
  • D 12(aL22+bL33)

Step-by-Step Verified Solution

Given Restoring force, F = ax + bx2

Work done in stretching the rubber-band by a distance dx is

dW=Fdx=(ax+bx2)dx

Intergrating both sides,

W=∫0Laxdx+∫0Lbx2dx

= [ax22+bx33]0L

= aL22+bL33

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