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QJEEM14Ph68f4: JEE Main 2014 Physics - Class 11 JEEM14Ph68f4 Solution: From a tower of height H, a particle is thrown vertically…

From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is:

Multiple Choice Options

  • A 2gH = n2u2
  • B gH = (n - 2)2u2
  • C 2gH = nu2(n - 2)
  • D gH = (n - 2)u2

Step-by-Step Verified Solution

JEE Main 2014 (Offline) Physics - Motion in a Straight Line Question 101 English Explanation

Time taken to reach highest point is t=ug

Time taken by the particle to reach the ground = nt=nug

Speed on reaching ground v=u2+2gH

Now, v=u+at

⇒u2+2gH=−u+gt

⇒t=u+u2+2gHg=nug (from question)

⇒2gH=n(n−2)u2

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