QJEEM14Ph0298: JEE Main 2014 Physics - Class 12 JEEM14Ph0298 Solution: The current voltage relation of diode is given by I = ( e 100 V …

Question

Verified Solution • 2025–26 Session moderate

The current voltage relation of diode is given by

I = (e^{100 V / T} - 1) m A,

where the applied voltage

V

is in volts and the temperature

T

is in degree kelvin. If a student makes an error measuring

\pm 0.01 V

while measuring the current of

5

m A

at

300

K,

what will be the error in the value of current on

m A

?

Accepted Answer

The current voltage relation of diode is

I = (e^{1000 V / T} - 1) m A

(given)

When,

I = 5 m A, e^{1000 V / T} = 6 m A

Also,

d l = (e^{1000 V / T}) \times \frac{1000}{T}

(By exponential function)

= (6 m A) \times \frac{1000}{300} \times (0.01)

= 0.2

m A

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