Verified Solution • 2025–26 Session moderate

QJEEM14Maac5d: JEE Main 2014 Mathematics - Class 12 JEEM14Maac5d Solution: The area of the region described by and is :

The area of the region described by
A={(x,y):x2+y2≤1A = \left\{ {\left( {x,y} \right):{x^2} + {y^2} \le 1} \right. and y2≤1−x}\left. {{y^2} \le 1 - x} \right\} is :

Multiple Choice Options

  • A π2−23{\pi \over 2} - {2 \over 3}
  • B π2+23{\pi \over 2} + {2 \over 3}
  • C π2+43{\pi \over 2} + {4 \over 3}
  • D π2−43{\pi \over 2} - {4 \over 3}

Step-by-Step Verified Solution

Given curves are x2+y2=1{x^2} + {y^2} = 1 and y2=1−x.{y^2} = 1 - x.

Intersection points are x=0,1x = 0,1

Area of shaded portion is the required area.

So, Required Area == Area of semi-circle ++ Area bounded by parabola

=πr22+2∫011−xdx= {{\pi {r^2}} \over 2} + 2\int\limits_0^1 {\sqrt {1 - x} dx}

=π2+2∫011−x dx= {\pi \over 2} + 2\int\limits_0^1 {\sqrt {1 - x} \,dx}

( As radius of circle =1=1 )

=π2+2[(1−x)3/2−3/2]01

=π2−43(−1)=π2+43= {\pi \over 2} - {4 \over 3}\left( { - 1} \right) = {\pi \over 2} + {4 \over 3} Sq. unit

Related Learning Resources & Exam Preparation