Verified Solution • 2025–26 Session moderate

QJEEM14Chb52e: JEE Main 2014 Chemistry - Class 11 JEEM14Chb52e Solution: If Z is a compressibility factor, van der Waals equation at low …

If Z is a compressibility factor, van der Waals equation at low pressure can be written as:

Multiple Choice Options

  • A Z = 1 + RTPbRT \over Pb
  • B Z = 1 - aVRTa \over VRT
  • C Z = 1 - PbRTPb \over RT
  • D Z = 1 + PbRTPb \over RT

Step-by-Step Verified Solution

Compressibility factor (Z)=PVRT\left( Z \right) = {{PV} \over {RT}}

(For one mole of real gas)

van der Waals equation

(P+aV2)(V−b)=RT\left( {P + {a \over {{V^2}}}} \right)\left( {V - b} \right) = RT

At low pressure, volume is very large and hence correction term bb can be neglected in comparison to very large volume of V.V.

i.e.    V−b≈V\,\,\,V - b \approx V

(P+aV2)V=RT;\left( {P + {a \over {{V^2}}}} \right)V = RT;

PV+aV=RTPV + {a \over V} = RT

PV=RT−aV;PV = RT - {a \over V};

PVRT=1−aVRT{{PV} \over {RT}} = 1 - {a \over {VRT}}

Hence,    z=1−aVRT\,\,\,z = 1 - {a \over {VRT}}

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