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QJEEM13Mae1f8: JEE Main 2013 Physics - Class 11 JEEM13Mae1f8 Solution: If the vectors and are the sides of a triangle then the length…

If the vectors AB→=3i^+4k^\overrightarrow {AB} = 3\widehat i + 4\widehat k and AC→=5i^−2j^+4k^\overrightarrow {AC} = 5\widehat i - 2\widehat j + 4\widehat k are the sides of a triangle ABC,ABC, then the length of the median through AA is :

Multiple Choice Options

  • A 18\sqrt {18}
  • B 72\sqrt {72}
  • C 33\sqrt {33}
  • D 45\sqrt {45}

Step-by-Step Verified Solution

As MM is mid point of BCBC

∴\therefore AM→=12(AB→+AC→)\overrightarrow {AM} = {1 \over 2}\left( {\overrightarrow {AB} + \overrightarrow {AC} } \right)

=4i→+j→+4k→= 4\overrightarrow i + \overrightarrow j + 4\overrightarrow k

Length of median AMAM

=16+1+16=33= \sqrt {16 + 1 + 16} = \sqrt {33}

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