Verified Solution • 2025–26 Session moderate

QJEEM13Ma1382: JEE Main 2013 Mathematics - Class 12 JEEM13Ma1382 Solution: If the lines and are coplanar, then can have :

If the lines x−21=y−31=z−4−k{{x - 2} \over 1} = {{y - 3} \over 1} = {{z - 4} \over { - k}} and x−1k=y−42=z−51{{x - 1} \over k} = {{y - 4} \over 2} = {{z - 5} \over 1} are coplanar, then kk can have :

Multiple Choice Options

  • A any value
  • B exactly one value
  • C exactly two values
  • D exactly three values

Step-by-Step Verified Solution

Given lines will be coplanar

If |−11111−kk21|=0

⇒−1(1+2k)−(1+k2)+1(2−k)=0\Rightarrow - 1\left( {1 + 2k} \right) - \left( {1 + {k^2}} \right) + 1\left( {2 - k} \right) = 0

⇒k=0,−3\Rightarrow k = 0, - 3

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