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QJEEM13Chf24c: JEE Main 2013 Chemistry - Class 11 JEEM13Chf24c Solution: The molarity of a solution obtained by mixing 750 mL of 0.5 (M) …

The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCl with 250 mL of 2(M) HCl will be:

Multiple Choice Options

  • A 1.00 M
  • B 1. 75 M
  • C 0.975 M
  • D 0.875 M

Step-by-Step Verified Solution

The formula for molarity of mixture of two substance is = M1V1+M2V2V1+V2{{{M_1}{V_1} + {M_2}{V_2}} \over {{V_1} + {V_2}}}

Here M1=0.5{M_1} = 0.5 , V1=750{V_1} = 750 , M2=2{M_2} = 2 , V2=250{V_2} = 250

∴\therefore Molarity of mixture = 0.5×750+2×250750+250{{0.5 \times 750 + 2 \times 250} \over {750 + 250}}

= 375+5001000{{375 + 500} \over {1000}}

= 8751000{{875} \over {1000}}

= 0.875

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