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QJEEM13Chcbab: JEE Main 2013 Chemistry - Class 12 JEEM13Chcbab Solution: Which of the following arrangements does not represent the…

Which of the following arrangements does not represent the correct order of the property stated against it?

Multiple Choice Options

  • A Ni2+ < Co2+ < Fe2+ < Mn2+ : ionic size
  • B Co3+ < Fe3+ < Cr3+ < Sc3+ : stability in aqueous solution
  • C Sc < Ti < Cr < Mn : number of oxidation states
  • D V2+ < Cr2+ < Mn2+ < Fe2+ : paramagnetic behaviour

Step-by-Step Verified Solution

(1)

V = 3d34s2 V2+ = 3d3 = 3 unpaired electron
Cr = 3d54s1 Cr2+ = 3d4 = 4 unpaired electron
Mn = 3d54s2 Mn2+ = 3d5 = 5 unpaired electron
Fe = 3d64s2 Fe2+ = 3d6 = 4 unpaired electron


hence the correct order of paramagnetic behaviour

{V^{2 + }} &lt; Cr{}^{2 + } = F{e^{2 + }} &lt; M{n^{2 + }}

(2)     \,\,\,\,

For the same oxidation state, the-ionic radii generally dcdc -creases as the atomic number increases in a particular transition series.

Hence the order is

M{n^{ + + }} &gt; F{e^{ + + }} &gt; C{o^{ + + }} &gt; N{i^{ + + }}

(3)

In solution, the stability of the compounds depends upon electrode potentials, SEPSEP of the transitions metal ions are given as

Co3+/Co=+1.97,   Fe3+/Fe=+0.77;C{o^{3 + }}/Co = + 1.97,\,\,\,F{e^{3 + }}/Fe = + 0.77;

Cr3+/Cr2+=−0.41,  Sc3+C{r^{3 + }}/C{r^{2 + }} = - 0.41,\,\,S{c^{3 + }} is highly stable as it does not show +2+2 O.O. S.S.

(4)

Sc−(+2),(+3)Sc - \left( { + 2} \right),\left( { + 3} \right)

Ti−(+2),(+3),(+4)Ti - \left( { + 2} \right),\left( { + 3} \right),\left( { + 4} \right)

Cr−(+1),(+2),(+3),(+4),(+5),(+6)Cr - \left( { + 1} \right),\left( { + 2} \right),\left( { + 3} \right),\left( { + 4} \right),\left( { + 5} \right),\left( { + 6} \right)

Mn−(+2),(+3),(+4),(+5),(+6),(+7)Mn - \left( { + 2} \right),\left( { + 3} \right),\left( { + 4} \right),\left( { + 5} \right),\left( { + 6} \right),\left( { + 7} \right)

i.e.\,Sc &lt; Ti &lt; Cr = Mn

Ea=53598.6J/mol{E_a} = 53598.6J/mol

=53.6 kJ/mol.= 53.6\,kJ/mol.

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