Verified Solution • 2025–26 Session moderate

QJEEM13Ch289e: JEE Main 2013 Chemistry - Class 11 JEEM13Ch289e Solution: Stability of the species Li 2 , and increases in the order of:

Stability of the species Li2, Li2−Li_2^− and Li2+Li_2^+ increases in the order of:

Multiple Choice Options

  • A Li2 < Li2+Li_2^+ < Li2−Li_2^-
  • B Li2+Li_2^+ < Li2−Li_2^- < Li2
  • C Li2−Li_2^- < Li2+Li_2^+ < Li2
  • D Li2−Li_2^- < Li2 < Li2+Li_2^+

Step-by-Step Verified Solution

Li2 = σ1s2  σ1s2∗ {\sigma _{1{s^2}}}\,\,\sigma _{1{s^2}}^ * \, σ2s2 {\sigma _{2{s^2}}} \,

∴\therefore Bond order = 12(4−2){1 \over 2}\left( {4 - 2} \right) = 1

Li2+Li_2^+ = σ1s2  σ1s2∗ {\sigma _{1{s^2}}}\,\,\sigma _{1{s^2}}^ * \, σ2s1 {\sigma _{2{s^1}}} \,

∴\therefore Bond order = 12(3−2){1 \over 2}\left( {3 - 2} \right) = 0.5

Li2−Li_2^- = σ1s2  σ1s2∗ {\sigma _{1{s^2}}}\,\,\sigma _{1{s^2}}^ * \, σ2s2  σ1s1∗ {\sigma _{2{s^2}}} \,\,\sigma _{1{s^1}}^ * \,

∴\therefore Bond order = 12(4−3){1 \over 2}\left( {4 - 3} \right) = 0.5

The bond order of Li2+Li_2^+ and Li2−Li_2^- is same but Li2+Li_2^+ is more stable than Li2−Li_2^- because Li2+Li_2^+ is smaller in size and has 2 electrons in antibonding orbitals whereas Li2−Li_2^- has 3 electrons in antibonding orbitals. Hence Li2+Li_2^+ is more stable than Li2−Li_2^- .

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