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QJEEM12Phbe28: JEE Main 2012 Physics - Class 12 JEEM12Phbe28 Solution: The figure shows an experimental plot for discharging of a…

The figure shows an experimental plot for discharging of a capacitor in an R-C circuit. The time constant τ\tau of this circuit lies between AIEEE 2012 Physics - Capacitor Question 102 English

Multiple Choice Options

  • A 100 sec and 150 sec
  • B 0 and 50 sec
  • C 50 sec and 100 sec
  • D 150 sec and 200 sec

Step-by-Step Verified Solution

During discharging of a capacitor, V = V0 e−tτ{e^{ - {t \over \tau }}}

At t = τ\tau ,

V = V0e{{{V_0}} \over e} = 0.37V0

From the graph, t = 0, V0 = 25 V

∴\therefore V = 0.37 ×\times 25 = 9.25 V

This voltage will occur at time between 100 sec and 150 sec. Hence, time constant τ\tau of this circuit lies between 100 sec and 150 sec.

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