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QJEEM12Ph0ebc: JEE Main 2012 Physics - Class 12 JEEM12Ph0ebc Solution: Hydrogen atom is excited from ground state to another state…

Hydrogen atom is excited from ground state to another state with principal quantum number equal to 4.4. Then the number of spectral lines in the emission spectra will be :

Multiple Choice Options

  • A 22
  • B 33
  • C 55
  • D 66

Step-by-Step Verified Solution

The possible number of the spectral lines is given

=n(n−1)2=4(4−1)2=6= {{n\left( {n - 1} \right)} \over 2} = {{4\left( {4 - 1} \right)} \over 2} = 6

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