QJEEM12Ch205f: JEE Main 2012 Chemistry - Class 11 JEEM12Ch205f Solution: The electrons identified by quantum numbers n and l : (a) n =…

(a) n = 4, $$l$$ = 1 (p-subshell), so 4p
(b) n = 4, $$l$$ = 0 (s-subshell), so 4s
(c) n = 3, $$l$$ = 2 (d-subshell), so 3d
(d) n = 3, $$l$$ = 1 (p-subshell), so 3p

Accroding to the Bohr ( n + $$l$$ ) rule,
Enery order of the subshell : 3p < 4s < 3d < 4p

Note: When two orbital have the same value of ( n + $$l$$ ) then the orbital which have lower value of n will be filled first.