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QJEEM11Phfa08: JEE Main 2011 Physics - Class 12 JEEM11Phfa08 Solution: A fully charged capacitor C with initial charge q 0 is…

A fully charged capacitor C with initial charge q0 is connected to a coil of self inductance L at t=0. The time at which the energy is stored equally between the electric and the magnetic fields is :

Multiple Choice Options

  • A π4LC
  • B 2πLC
  • C LC
  • D πLC

Step-by-Step Verified Solution

Energy stored in magnetic field =12Li2

Energy stored in electric field =12q2C

∴ 12Li2=12q2C

Also q=q0cosωt and ω=1LC

On solving t=π4LC

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