QJEEM11Phe594: JEE Main 2011 Physics - Class 12 JEEM11Phe594 Solution: Let x - z plane be the boundary between two transparent media.…

Question

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Let

x

-

z

plane be the boundary between two transparent media. Medium

1

in

z \geq 0

has a refractive index of

\sqrt{2}

and medium

2

with

z < 0

has a refractive index of

\sqrt{3} .

A ray of light in medium

1

given by the vector

\vec{A} = 6 \sqrt{3} \hat{i} + 8 \sqrt{3} \hat{j} - 10 \hat{k}

is incident on the plane of separation. The angle of refraction in medium

2

is:

Accepted Answer

Angle of incidence is given by

\cos (π - i) = \frac{(6 \sqrt{3} \hat{i} + 8 \sqrt{3} \hat{j} - 10 \hat{k}) . \hat{k}}{20}

- \cos i = - \frac{1}{2}

∠ i = 60^{\circ}

From Snell's law,

\sqrt{2} \sin i = \sqrt{3} \sin r

\Rightarrow

∠ r = 45^{\circ}

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