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QJEEM11Phb45e: JEE Main 2011 Physics - Class 12 JEEM11Phb45e Solution: Energy required for the electron excitation in from the first…

Energy required for the electron excitation in Li++L{i^{ + + }} from the first to the third Bohr orbit is :

Multiple Choice Options

  • A 36.336.3 eVeV
  • B 108.8108.8 eVeV
  • C 122.4122.4 eVeV
  • D 12.112.1 eVeV

Step-by-Step Verified Solution

Energy of excitation,

ΔE=13.6 Z2(1n12−1n22)eV\Delta E = 13.6\,{Z^2}\left( {{1 \over {n_1^2}} - {1 \over {n_2^2}}} \right)eV

⇒ΔE=13.6(3)2(112−132)=108.8 eV\Rightarrow \Delta E = 13.6{\left( 3 \right)^2}\left( {{1 \over {{1^2}}} - {1 \over {{3^2}}}} \right) = 108.8\,eV

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