Verified Solution • 2025–26 Session moderate

QJEEM11Ph4049: JEE Main 2011 Physics - Class 11 JEEM11Ph4049 Solution: 100 g of water is heated from 30 ∘ C to 50 ∘ C . Ignoring the…

100g of water is heated from 30∘C to 50∘C. Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is 4184 J/kg/K):

Multiple Choice Options

  • A 8.4 kJ
  • B 84 kJ
  • C 2.1 kJ
  • D 4.2 kJ

Step-by-Step Verified Solution

ΔU=ΔQ=mcΔT
=100×10−3×4184(50−30)≈8.4kJ

Related Learning Resources & Exam Preparation