Verified Solution • 2025–26 Session moderate

QJEEM11Ma5616: JEE Main 2011 Mathematics - Class 11 JEEM11Ma5616 Solution: If ω ( ≠ 1 ) is a cube root of unity, and ( 1 + ω ) 7 = A + B ω …

If ω(≠1) is a cube root of unity, and (1+ω)7=A+Bω. Then (A,B) equals :

Multiple Choice Options

  • A (1 ,1)
  • B (1, 0)
  • C (- 1 ,1)
  • D (0 ,1)

Step-by-Step Verified Solution

(1+ω)7=A+Bω;(−ω2)7=A+Bω

−ω2=A+Bω;1+ω=A+Bω

⇒A=1,B=1.

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