Verified Solution • 2025–26 Session moderate

QJEEM11Ch43ee: JEE Main 2011 Chemistry - Class 12 JEEM11Ch43ee Solution: Ethylene glycol is used as an antifreeze in a cold climate.…

Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at −6oC will be : [Kf for water = 1.86 K kg mol−1 , and molar mass of ethylene glycol = 62 g mol−1 )

Multiple Choice Options

  • A 204.30 g
  • B 400.00 g
  • C 304.60 g
  • D 804.32 g

Step-by-Step Verified Solution

Given Kr=1.86 K kg mol−1{K_r} = 1.86\,K\,kg\,mo{l^{ - 1}}

ΔTf=0−(−6)=6∘C\Delta {T_f} = 0 - \left( { - 6} \right) = {6^ \circ }C

As we know that

ΔTf=Kf×  molality\Delta {T_f} = {K_f} \times \,\,molality

=Kf×1000×mass  of  solutemolar  mass  of  solute  ×  mass  of  solvent  in  kg= {{{K_f} \times 1000 \times mass\,\,of\,\,solute} \over {molar\,\,mass\,\,of\,\,solute\,\, \times \,\,mass\,\,of\,\,solvent\,\,in\,\,kg}}

Substituting given values in formula

6=1.86×1000×w62×4;6 = {{1.86 \times 1000 \times w} \over {62 \times 4}};

     w=0.8 kg=800 gm\,\,\,\,\,w = 0.8\,kg = 800\,gm

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