Verified Solution • 2025–26 Session moderate

QJEEM11Ch1eb6: JEE Main 2011 Chemistry - Class 11 JEEM11Ch1eb6 Solution: The entropy change involved in the isothermal reversible…

The entropy change involved in the isothermal reversible expansion of 2 moles of an ideal gas from a volume of 10 dm3 to a volume of 100 dm3 at 27oC is :

Multiple Choice Options

  • A 35.8 J mol-1 K−1
  • B 32.3 J mol-1 K−1
  • C 42.3 J mol-1 K−1
  • D 38.3 J mol-1 K−1

Step-by-Step Verified Solution

Entropy change for an isothermal reversible process is given by

ΔS=nR lnV2V1\Delta S = nR{\mkern 1mu} ln{{{V_2}} \over {{V_1}}}

=2×8.314×2.303log 10010= 2 \times 8.314 \times 2.303log\,{{100} \over {10}}

=38.3 J mol−1  K−1= 38.3\,J\,mo{l^{ - 1}}\,\,{K^{ - 1}}

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