QJEEM10Ma9cfb: JEE Main 2010 Mathematics - Class 12 JEEM10Ma9cfb Solution: The area bounded by the curves y = cos ⁡ x and y = sin ⁡ x…

Question

Verified Solution • 2025–26 Session moderate

The area bounded by the curves

y = \cos x

and

y = \sin x

between the ordinates

x = 0

and

x = \frac{3 π}{2}

is

Accepted Answer

∴

Required area

= [\int_{0}^{\frac{π}{4}} (\cos x - \sin x) d x +

\int_{\frac{π}{4}}^{\frac{5 π}{4}} (\sin x - \cos x) d x +

\int_{\frac{5 π}{4}}^{\frac{3 π}{2}} (\cos x - \sin x) d x

= 4 \sqrt{2} - 2

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