Verified Solution • 2025–26 Session moderate

QJEEM10Cha80e: JEE Main 2010 Chemistry - Class 11 JEEM10Cha80e Solution: Ionisation energy of He + is 19.6 x 10 –18 J atom –1 . The…

Ionisation energy of He+ is 19.6 x 10–18 J atom–1. The energy of the first stationary state (n = 1) of Li2+ is

Multiple Choice Options

  • A 4.41 x 10–16 J atom–1
  • B -4.41 x 10–17 J atom–1
  • C -2.2 x 10–15 J atom–1
  • D 8.82 x 10–17 J atom–1

Step-by-Step Verified Solution

Ionisation energy(IE) - It is the energy required to move an electron from ground state to infinity.

IE = E∞−E1{E_\infty } - {E_1} = 0−E10 - {E_1} = −E1- {E_1}

∴\therefore E1 of He+ = - 19.6 x 10–18 J atom–1

Energy of a species at n state,

(En)species = (En)hydrogen ×\times Z2

∴\therefore (E1)hydrogen = −19.6×10−184{{ - 19.6 \times {{10}^{ - 18}}} \over 4} [ For He, Z = 2 ]

(E1)Li+2 = −19.6×10−184×32{{ - 19.6 \times {{10}^{ - 18}}} \over 4} \times {3^2}

= -4.41 x 10–17 J atom–1

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