QJEEM08Ma5b53: JEE Main 2008 Mathematics - Class 12 JEEM08Ma5b53 Solution: A die is thrown. Let A be the event that the number obtained is …

Question

Verified Solution • 2025–26 Session moderate

A die is thrown. Let

A

be the event that the number obtained is greater than

3.

Let

B

be the event that the number obtained is less than

5.

Then

P (A \cup B)

is :

Accepted Answer

No of outcome for a die = { 1, 2, 3, 4, 5, 6 }
According to the question,

A = { 4, 5, 6 }

∴

P(A) =

\frac{3}{6}

B = { 1, 2, 3, 4 }

∴

P(A) =

\frac{4}{6}

A

\cap

B = { 4 }

So P(A

\cap

B) =

\frac{1}{6}

We know,

P (A \cup B)

=

P (A)

+

P (B)

-

P (A \cap B)

∴

P (A \cup B)

=

\frac{3}{6}

+

\frac{4}{6}

-

\frac{1}{6}

=

\frac{7 - 1}{6}

=

\frac{6}{6}

= 1

∴

Option (C) is correct.

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