Verified Solution • 2025–26 Session moderate

QJEEM08Ch32f7: JEE Main 2008 Chemistry - Class 12 JEEM08Ch32f7 Solution: The coordination number and the oxidation state of the element…

The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylene diamine) are, respectively,

Multiple Choice Options

  • A 6 and 2
  • B 4 and 2
  • C 4 and 3
  • D 6 and 3

Step-by-Step Verified Solution

In the given complex we have two bidentate ligands (i.e. en and C2O4 ), so coordination number of E is 6 (2×2+1×2=6)

Let the oxidation state of E in complex be x,

then [x+(−2)=1] or x−2=1

or x=+3, so its oxidation state is +3

Thus option (d) is correct.

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