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QJEEM08Ch2a7a: JEE Main 2008 Chemistry - Class 12 JEEM08Ch2a7a Solution: Amount of oxalic acid present in a solution can be determined…

Amount of oxalic acid present in a solution can be determined by its titration with KMnO4KMn{O_4} solution in the presence of H2SO4.{H_2}S{O_4}. The titration gives unsatisfactory result when carried out in the presence of HCl,HCl, because HClHCl :

Multiple Choice Options

  • A gets oxidised by oxalic acid to chlorine
  • B furnishes H+{H^ + } ions in addition to those from oxalic acid
  • C reduces permanganate to Mn2+M{n^{2 + }}
  • D oxaidises oxalic acid to carbon doxide and water

Step-by-Step Verified Solution

The titration of oxalic acid with KMnO4KMnO{}_4 in presence of HClHCl gives unsatisfactory result because of the fact that KMnO4KMn{O_4} can also oxidise HClHCl along with oxalic acid. HClHCl on oxidation gives Cl2C{l_2} and HClHCl reduces KMnO4KMnO{}_4 to Mn2+M{n^{2 + }} thus the correct answer is (c).(c).

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