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QJEEM07Pha5b7: JEE Main 2007 Physics - Class 12 JEEM07Pha5b7 Solution: Two lenses of power and are in contact with each other. The…

Two lenses of power −15-15 DD and +5+5 DD are in contact with each other. The focal length of the combination is

Multiple Choice Options

  • A +10 cm+ 10\,cm
  • B −20 cm- 20\,cm
  • C −10 cm- 10\,cm
  • D +20 cm+ 20\,cm

Step-by-Step Verified Solution

Power of combination is given by

P=P1+P2=(−15+5)DP = {P_1} + {P_2} = \left( { - 15 + 5} \right)D          =−10D.\,\,\,\,\,\,\,\,\, = - 10D.

Now, P=1f⇒f=1P=1−10P = {1 \over f} \Rightarrow f = {1 \over P} = {1 \over { - 10}} metre

∴\therefore f=−(110×100)cm=−10 cm.f = - \left( {{1 \over {10}} \times 100} \right)cm = - 10\,cm.

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