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QJEEM07Ph7f93: JEE Main 2007 Physics - Class 12 JEEM07Ph7f93 Solution: A charged particle with charge q enters a region of constant,…

A charged particle with charge q enters a region of constant, uniform and mutually orthogonal fields E→ and B→ with a velocity v→ perpendicular to both E→ and B→, and comes out without any change in magnitude or direction of v→. Then

Multiple Choice Options

  • A v→=B→×E→/E2
  • B v→=E→×B→/B2
  • C v→=B→×E→/B2
  • D v→=E→×B→/E2

Step-by-Step Verified Solution

Here, E→ and B→ are perpendicular to each other and the velocity v→ does not change; therefore

qE=qvB⇒v=EB

Also, |E→×B→B2|=EBsin⁡θB2

=EBsin⁡90∘B2=EB=|v→|=v

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