QJEEM07Ph7d66: JEE Main 2007 Physics - Class 11 JEEM07Ph7d66 Solution: For the given uniform square lamina , whose center is

Question

Verified Solution • 2025–26 Session moderate

For the given uniform square lamina

ABCD

, whose center is

O,

Accepted Answer

By perpendicular axes theorem,

{I_x} = {I_x} + {I_y}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,

or,\,\,\,\,\,\,\,\,\,\,\,\,\,{I_z} = 2{I_y}

( as

{I_x} = {I_y}

by symmetry of the figure)

\therefore

{I_{EF}} = {{{I_z}} \over 2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,....\left( i \right)

By perpendicular axes theorem,

{I_z} = {I_{AC}} + {I_{BD}} = 2{I_{AC}}

(As

{I_{AC}} = {I_{BD}}

by symmetry of the figure)

\therefore

{I_{AC}} = {{{I_z}} \over 2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( {ii} \right)

From

(i)

and

(ii),

we get

{I_{EF}} = {I_{AC}}.

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