Verified Solution • 2025–26 Session moderate

QJEEM07Ph463e: JEE Main 2007 Physics - Class 12 JEEM07Ph463e Solution: Which of the following transitions in hydrogen atoms emit…

Which of the following transitions in hydrogen atoms emit photons of highest frequency ?

Multiple Choice Options

  • A n=1n = 1 to n=2n=2
  • B n=2n = 2 to n=6n=6
  • C n=6n = 6 to n=2n=2
  • D n=2n = 2 to n=1n=1

Step-by-Step Verified Solution

We have no find the frequency of emitted photons. For emission of photons the transition must take place from a higher energy level to a lower energy level which are given only in options (c)(c) and (d)(d) .

Frequency is given by

hv=−13.6(1n22−1n12)hv = - 13.6\left( {{1 \over {n_2^2}} - {1 \over {n_1^2}}} \right)

For transition from n=6n=6 to n=2,n=2,

v1=−13.6h(162−122){v_1} = {{ - 13.6} \over h}\left( {{1 \over {{6^2}}} - {1 \over {{2^2}}}} \right)

=29×(13.6h)= {2 \over 9} \times \left( {{{13.6} \over h}} \right)

For transition from n=2n=2 to n=1,n=1,

v2=−13.6h(122−112){v_2} = {{ - 13.6} \over h}\left( {{1 \over {{2^2}}} - {1 \over {{1^2}}}} \right)

=34×(13.6h).= {3 \over 4} \times \left( {{{13.6} \over h}} \right).

∴\therefore {v_1} > {v_2}

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