QJEEM07Ph412b: JEE Main 2007 Physics - Class 12 JEEM07Ph412b Solution: In an a . c . circuit the voltage applied is E = E 0 sin ω t .…

Question

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In an

a . c .

circuit the voltage applied is

E = E_{0} \sin ω t .

The resulting current in the circuit is

I = I_{0} \sin (ω t - \frac{π}{2}) .

The power consumption in the circuit is given by

Accepted Answer

KEY CONCEPT : We know that power consumed in a.c. circuit is given by,

P = E_{r m s} I_{r m s} \cos ϕ

Here,

E = E_{0} \sin ω t

I = I_{0} \sin (ω t - \frac{π}{2})

which implies that the phase difference,

ϕ = \frac{π}{2}

∴

P = E_{r m s} . I_{r m s} . \cos \frac{π}{2} = 0

(

as

\cos \frac{π}{2} = 0)

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