Verified Solution • 2025–26 Session moderate

QJEEM07Maa3c5: JEE Main 2007 Mathematics - Class 12 JEEM07Maa3c5 Solution: Let and Then which one of the following is true?

Let I=∫01sin⁡xxdxI = \int\limits_0^1 {{{\sin x} \over {\sqrt x }}dx} and J=∫01cos⁡xxdx.J = \int\limits_0^1 {{{\cos x} \over {\sqrt x }}dx} . Then which one of the following is true?

Multiple Choice Options

  • A 1>231 > {2 \over 3} and J>2J > 2
  • B 1<231 < {2 \over 3} and J<2J < 2
  • C 1<231 < {2 \over 3} and J>2J > 2
  • D 1>231 > {2 \over 3} and J<2J < 2

Step-by-Step Verified Solution

We know that {{\sin x} \over x} &lt; 1, for x∈(0,1)x \in \left( {0,1} \right)

\Rightarrow {{\sin x} \over {\sqrt x }} &lt; \sqrt x on x∈(0,1)x \in \left( {0,1} \right)

\Rightarrow \int\limits_0^1 {{{\sin x} \over {\sqrt x }}dx &lt; \int\limits_0^1 {\sqrt x dx} = \left[ {{{2{x^{3/2}}} \over 3}} \right]} _0^1

\Rightarrow \int\limits_0^1 {{{\sin x} \over {\sqrt x }}} dx &lt; {2 \over 3} \Rightarrow I &lt; {2 \over 3}

Also {{\cos x} \over {\sqrt x }} &lt; {1 \over {\sqrt x }} for x∈(0,1)x \in \left( {0,1} \right)

\Rightarrow \int\limits_0^1 {{{\cos x} \over {\sqrt x }}dx &lt; \int\limits_0^1 {{x^{ - 1/2}}dx} }

              =[2x]01=2\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \left[ {2\sqrt x } \right]_0^1 = 2

\Rightarrow \int\limits_0^1 {{{\cos x} \over {\sqrt x }}dx &lt; 2}

\Rightarrow J &lt; 2

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