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QJEEM07Ma35b8: JEE Main 2007 Mathematics - Class 11 JEEM07Ma35b8 Solution: Let A , B and C be the vertices of a right angled triangle with …

Let A (h,k)\left( {h,k} \right) , B (1,1)\left( {1,1} \right) and C (2,1)(2, 1) be the vertices of a right angled triangle with AC as its hypotenuse. If the area of the triangle is 11 square unit, then the set of values which ′k′'k' can take is given by :

Multiple Choice Options

  • A {−1,3}\left\{ { - 1,3} \right\}
  • B {−3,−2}\left\{ { - 3, - 2} \right\}
  • C {1,3}\left\{ { 1,3} \right\}
  • D {0,2}\left\{ {0,2} \right\}

Step-by-Step Verified Solution

Given : The vertices of a right angled triangle A(1,k),A\left( {1,k} \right),

B(1,1)B\left( {1,1} \right) and C(2,1)C\left( {2,1} \right) and area of ΔABC=1\Delta ABC = 1 square unit

AIEEE 2007 Mathematics - Straight Lines and Pair of Straight Lines Question 144 English Explanation

We know that, area of night angled triangle

=12×BC×AB=1=12(1)∣(k−1)∣= {1 \over 2} \times BC \times AB = 1 = {1 \over 2}\left( 1 \right)\left| {\left( {k - 1} \right)} \right|

⇒±(k−1)=2⇒k=−1,3\Rightarrow \pm \left( {k - 1} \right) = 2 \Rightarrow k = - 1,3

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