QJEEM07Ma1894: JEE Main 2007 Mathematics - Class 12 JEEM07Ma1894 Solution: Two aeroplanes I and I I bomb a target in succession. The…

Question

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Two aeroplanes

I

and

I

I

bomb a target in succession. The probabilities of

I

and

I

I

scoring a hit correctly are

0.3

and

0.2,

respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is :

Accepted Answer

The desired probability

= (0.7) (0.2) + (0.7) (0.8) (0.7) (0.2) + (0.7) (0.8) (0.7) (0.8) (0.7) (0.2) + .......

= 0.14 [1 + (0.56) + (0.56)² + .......]

= 0.14 $(\frac{1}{1 - 0.56}) = \frac{0.14}{0.44} = \frac{7}{22}$ = 0.32

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