Verified Solution • 2025–26 Session moderate

QJEEM07Ma0b5f: JEE Main 2007 Mathematics - Class 12 JEEM07Ma0b5f Solution: If D =

If D=|11111+x1111+y| for x≠0,y≠0,x \ne 0,y \ne 0, then DD is :

Multiple Choice Options

  • A divisible by xx but not yy
  • B divisible by yy but not xx
  • C divisible by neither xx nor yy
  • D divisible by both xx and yy

Step-by-Step Verified Solution

Given, D=|11111+x1111+y|

Apply    R2→R2−R1\,\,\,{R^2} \to {R_2} - {R_1}     \,\,\,\,

and     \,\,\,\, R→R3−R1R \to {R_3} - {R_1}

∴\therefore D=|1110x000y|=xy

Hence, DD is divisible by both xx and yy

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