QJEEM07Ch7bfe: JEE Main 2007 Chemistry - Class 12 JEEM07Ch7bfe Solution: The cell, Zn

Question

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The cell, Zn | Zn²⁺ (1M) || Cu²⁺ (1M) | Cu(

E_{cell}^o

= 1.10V) was allowed to be completely discharged at 298 K. The relative concentration of Zn²⁺ to Cu²⁺

\left[ {{{\left[ {Z{n^{2 + }}} \right]} \over {\left[ {C{u^{2 + }}} \right]}}} \right]

is

Accepted Answer

{E_{cell}} = 0;\,\,

when cell is completely discharged.

{E_{cell}} = {E^ \circ }_{cell} - {{0.059} \over 2}\log \left( {{{\left[ {Z{n^{2 + }}} \right]} \over {\left[ {C{u^{2 + }}} \right]}}} \right)

or

\,\,\,\,0 - 1.1 - {{0.059} \over 2}\log \left( {{{\left[ {Z{n^{2 + }}} \right]} \over {\left[ {C{u^{2 + }}} \right]}}} \right)

\log \left( {{{\left[ {Z{n^{2 + }}} \right]} \over {\left[ {C{u^{2 + }}} \right]}}} \right) = {{2 \times 1.1} \over {0.059}} = 37.3

\therefore

\,\,\,\,\left( {{{\left[ {Z{n^{2 + }}} \right]} \over {\left[ {C{u^{2 + }}} \right]}}} \right) = {10^{37.3}}

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