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QJEEM07Ch39e7: JEE Main 2007 Chemistry - Class 11 JEEM07Ch39e7 Solution: The pK a of a weak acid (HA) is 4.5. The pOH of an aqueous…

The pKa of a weak acid (HA) is 4.5. The pOH of an aqueous buffered solution of HA in which 50% of the acid is ionized is :

Multiple Choice Options

  • A 7
  • B 4.5
  • C 2.5
  • D 9.5

Step-by-Step Verified Solution

For acidic buffer pH=pKa+log⁡[saltacid]pH = p{K_a} + \log \left[ {{{salt} \over {acid}}} \right]

or    pH=pKa+log⁡[A−][HA]\,\,\,pH = p{K_a} + \log {{\left[ {{A^ - }} \right]} \over {\left[ {HA} \right]}}

Given pKa=4.5  p{K_a} = 4.5\,\, and acid is 50%50\% ionised.

[HA]=[A−]   \left[ {HA} \right] = \left[ {{A^ - }} \right]\,\,\, (when acid is 50%50\% ionised)

∴\therefore    pH=pKa+log⁡ 1\,\,\,pH = p{K_a} + \log \,1

∴\therefore    pH=pKa=4.5\,\,\,pH = p{K_a} = 4.5

pOH=14−pHpOH = 14 - pH

=14−4.5= 14 - 4.5

=9.5= 9.5

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