Verified Solution • 2025–26 Session moderate

QJEEM06Ma1011: JEE Main 2006 Mathematics - Class 11 JEEM06Ma1011 Solution: In the ellipse, the distance between its foci is and minor axis …

In the ellipse, the distance between its foci is 66 and minor axis is 88 . Then its eccentricity is :

Multiple Choice Options

  • A 35{3 \over 5}
  • B 12{1 \over 2}
  • C 45{4 \over 5}
  • D 15{1 \over {\sqrt 5 }}

Step-by-Step Verified Solution

2ae=6⇒ae=3;  2b=8⇒b=42ae = 6 \Rightarrow ae = 3;\,\,2b = 8 \Rightarrow b = 4

b2=a2(1−e2);16=a2−a2e2{b^2} = {a^2}\left( {1 - {e^2}} \right);16 = {a^2} - {a^2}{e^2}

⇒a2=16+9=25\Rightarrow a{}^2 = 16 + 9 = 25

⇒a=5\Rightarrow a = 5

∴\therefore e=3a=35e = {3 \over a} = {3 \over 5}

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