Verified Solution • 2025–26 Session moderate

QJEEM06Chf2ee: JEE Main 2006 Chemistry - Class 12 JEEM06Chf2ee Solution: The molar conductivities and and at infinite dilution in water…

The molar conductivities ∧NaOAco\wedge _{NaOAc}^o and ∧HClo\wedge _{HCl}^o and at infinite dilution in water at 25oC are 91.0 and 426.2 Scm2/mol respectively. To calculate ∧HOAco\wedge _{HOAc}^o , the additional value required is

Multiple Choice Options

  • A ∧H2Oo\wedge _{{H_2}O}^o
  • B ∧KClo\wedge _{KCl}^o
  • C ∧NaOHo\wedge _{NaOH}^o
  • D ∧NaClo\wedge _{NaCl}^o

Step-by-Step Verified Solution

ΛCH3COOHo\Lambda _{C{H_3}COOH}^o is given by the following equation

ΛCH3COOHo=(ΛCH3COONao+ΛHClo)−(ΛNaClo)\Lambda _{C{H_3}COOH}^o = \left( {\Lambda _{C{H_3}COONa}^o + \Lambda _{HCl}^o} \right) - \left( {\Lambda _{NaCl}^o} \right)

Hence ΛNaCl∘\Lambda _{NaCl}^ \circ is required.

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring