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QJEEM06Che112: JEE Main 2006 Chemistry - Class 11 JEEM06Che112 Solution: Which of the following molecules/ions does not contain unpaired …

Which of the following molecules/ions does not contain unpaired electrons?

Multiple Choice Options

  • A O22−O_2^{2−}
  • B B2
  • C N2+N_2^+
  • D O2

Step-by-Step Verified Solution

(A) Molecular orbital configuration of O 22−_2^{2 - } (18 electrons) is

σ1s2 σ1s2∗ σ2s2 σ2s2∗ σ2pz2 π2px2 = π2py2 π2px2∗ = π2py2∗{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,{\sigma _{2{s^2}}}\,\sigma _{2{s^2}}^ * \,{\sigma _{2p_z^2}}\,{\pi _{2p_x^2}}\, = \,{\pi _{2p_y^2}}\,\pi _{2p_x^2}^ * \, = \,\pi _{2p_y^2}^ *

So O 22−_2^{2 - } has no unpaired electrons.

(B) Molecular orbital configuration of B2 (10 electrons) is

σ1s2 σ1s2∗  σ2s2  σ2s2∗  π2px1=π2py1{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,\,{\sigma _{2{s^2}}}\,\,\sigma _{2{s^2}}^ * \,\,{\pi _{2p_x^1}} = {\pi _{2p_y^1}}

Here in B2, 2 unpaired electrons present.

(C) Moleculer orbital configuration of N2+N_2^{ + } (13 electrons)

= σ1s2 σ1s2∗ σ2s2 σ2s2∗ π2px2 = π2py2 σ2pz1{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,{\sigma _{2{s^2}}}\,\sigma _{2{s^2}}^ * \,{\pi _{2p_x^2}}\, = \,{\pi _{2p_y^2}}\,{\sigma _{2p_z^1}}

Here in N2+N_2^{ + } , 1 unpaired electron present.

(D) Molecular orbital configuration of O2 (16 electrons) is

σ1s2  σ1s2∗ {\sigma _{1{s^2}}}\,\,\sigma _{1{s^2}}^ * \, σ2s2  σ2s2∗ {\sigma _{2{s^2}}}\,\,\sigma _{2{s^2}}^ * \, σ2pz2  π2px2=π2py2  π2px1∗  =π2py1∗{\sigma _{2p_z^2}}\,\,{\pi _{2p_x^2}} = {\pi _{2p_y^2}}\,\,\pi _{2p_x^1}^ * \,\, = \pi _{2p_y^1}^ *

So O 2_2 has 2 unpaired electrons.

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