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QJEEM06Ch80b8: JEE Main 2006 Chemistry - Class 12 JEEM06Ch80b8 Solution: The following mechanism has been proposed for the reaction of…

The following mechanism has been proposed for the reaction of NO with Br2 to form NOBr:
NO(g) + Br2 (g) ⇋\leftrightharpoons NOBr2 (g)
NOBr2 (g) + NO (g) →\to 2NOBr (g)
If the second step is the rate determining step, the order of the reaction with respect to NO(g) is

Multiple Choice Options

  • A 1
  • B 0
  • C 3
  • D 2

Step-by-Step Verified Solution

(i)         NO(g)+Br2(g)   ⇌ NOBr2(g)\left( i \right)\,\,\,\,\,\,\,\,\,NO\left( g \right) + B{r_2}\left( g \right)\,\,\,\rightleftharpoons\,NOB{r_2}\left( g \right)

(ii)NOBr2(g)+NO(g)⟶2NOBr(g)

Rate law equation =k[NOBr2][NO]= k\left[ {NOB{r_2}} \right]\left[ {NO} \right]

But NOBr2NOB{r_2} is intermediate and

must not appear in the rate law equation

from 11 st step KC=[NOBr2][NO][Br2]{K_C} = {{\left[ {NOB{r_2}} \right]} \over {\left[ {NO} \right]\left[ {B{r_2}} \right]}}

∴\therefore      [NOBr2]=KC[NO][Br2]\,\,\,\,\,\left[ {NOB{r_2}} \right] = {K_C}\left[ {NO} \right]\left[ {B{r_2}} \right]

∴\therefore     \,\,\,\, Rate law equation =k.KC[NO]2[Br2]= k.{K_C}{\left[ {NO} \right]^2}\left[ {B{r_2}} \right]

hence order of reaction is 22 w.r.t. NO.NO.

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