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QJEEM06Ch4ad3: JEE Main 2006 Chemistry - Class 11 JEEM06Ch4ad3 Solution: The alkene formed as a major product in the above elimination…

AIEEE 2006 Chemistry - Hydrocarbons Question 129 English

The alkene formed as a major product in the above elimination reaction is

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/b80d55c1076aa30024be1148e3fa1abb7beb10405c4e4530a456bf7d727a1052.webp
  • B https://ik.imagekit.io/novatra/photos/d49ae9e268e9465a4f2dec390b8d25fe193f9e6d951e2b90b885d7ed8d2b3ea2.webp
  • C https://ik.imagekit.io/novatra/photos/774a6e32d9ee3639a1d2d893d74ebc61bee12f230468beff8f9cbde2a28a9244.webp
  • D https://ik.imagekit.io/novatra/photos/e813630da04bf6be7a25e998e72cabc3691816df2e138310d4343c8a306ef67c.webp

Step-by-Step Verified Solution

Hofmann's rule : When theoretically more than one type of alkenes are possible in eliminations reaction, the alkene containing least alkylated double bond is formed as major product. Hence

AIEEE 2006 Chemistry - Hydrocarbons Question 129 English Explanation

NOTE : It is less stearically β\beta -hydrogen is removed

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